Math, asked by akshaya666, 6 months ago

(x^2+y^2-z^2)^2-(x^2-y^2+z^2)^2​

Answers

Answered by somasenthil21
0

Step-by-step explanation:

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Answered by XxItzAnvayaXx
2

Answer:

The formula for (x-y-z)^2(x−y−z)

The formula for (x-y-z)^2(x−y−z) 2

The formula for (x-y-z)^2(x−y−z) 2 is equal to x^2+y^2+z^2-2xy+2yz-2zxx

The formula for (x-y-z)^2(x−y−z) 2 is equal to x^2+y^2+z^2-2xy+2yz-2zxx 2

The formula for (x-y-z)^2(x−y−z) 2 is equal to x^2+y^2+z^2-2xy+2yz-2zxx 2 +y

The formula for (x-y-z)^2(x−y−z) 2 is equal to x^2+y^2+z^2-2xy+2yz-2zxx 2 +y 2

The formula for (x-y-z)^2(x−y−z) 2 is equal to x^2+y^2+z^2-2xy+2yz-2zxx 2 +y 2 +z

The formula for (x-y-z)^2(x−y−z) 2 is equal to x^2+y^2+z^2-2xy+2yz-2zxx 2 +y 2 +z 2

The formula for (x-y-z)^2(x−y−z) 2 is equal to x^2+y^2+z^2-2xy+2yz-2zxx 2 +y 2 +z 2 −2xy+2yz−2zx

Solutions

=(x)^2+(-y)^2+(z)^2+2.x.(-y)+2.(-y).(-z)+2.(-z).x=(x)

=(x)^2+(-y)^2+(z)^2+2.x.(-y)+2.(-y).(-z)+2.(-z).x=(x) 2

=(x)^2+(-y)^2+(z)^2+2.x.(-y)+2.(-y).(-z)+2.(-z).x=(x) 2 +(−y)

=(x)^2+(-y)^2+(z)^2+2.x.(-y)+2.(-y).(-z)+2.(-z).x=(x) 2 +(−y) 2

=(x)^2+(-y)^2+(z)^2+2.x.(-y)+2.(-y).(-z)+2.(-z).x=(x) 2 +(−y) 2 +(z)

=(x)^2+(-y)^2+(z)^2+2.x.(-y)+2.(-y).(-z)+2.(-z).x=(x) 2 +(−y) 2 +(z) 2

=(x)^2+(-y)^2+(z)^2+2.x.(-y)+2.(-y).(-z)+2.(-z).x=(x) 2 +(−y) 2 +(z) 2 +2.x.(−y)+2.(−y).(−z)+2.(−z).x

=(x)^2+(-y)^2+(z)^2+2.x.(-y)+2.(-y).(-z)+2.(-z).x=(x) 2 +(−y) 2 +(z) 2 +2.x.(−y)+2.(−y).(−z)+2.(−z).x=x^2+y^2+z^2-2xy+2yz-2zx

We know that, (x-y)=p(x−y)=p , substitute this in the above one, we get,

=( x - y ) ^ { 2 } + z ^ { 2 } - 2 p z } \\\\ { = x ^ { 2 } + y ^ { 2 } - 2 x y + z ^ { 2 } - 2 p z } \\\\ { = x ^ { 2 } + y ^ { 2 } - 2 x y + z ^ { 2 } - 2 ( x - y ) z } \\\\ { = x ^ { 2 } + y ^ { 2 } + z ^ { 2 } - 2 x y - 2 x z + 2 y z } \\\\ { ( x - y - z ) ^ { 2 }

= x ^ { 2 } + y ^ { 2 } + z ^ { 2 } - 2 x y + 2 y z - 2 x z }

Hence, proved the above driven formula.

Hence, proved the above driven formula.Thus, the formula for (x-y-z)^2(x−y−z)

Hence, proved the above driven formula.Thus, the formula for (x-y-z)^2(x−y−z) 2

Hence, proved the above driven formula.Thus, the formula for (x-y-z)^2(x−y−z) 2 will be

Hence, proved the above driven formula.Thus, the formula for (x-y-z)^2(x−y−z) 2 will be x^2+y^2+z^2-2xy+2yz-2xzx

Hence, proved the above driven formula.Thus, the formula for (x-y-z)^2(x−y−z) 2 will be x^2+y^2+z^2-2xy+2yz-2xzx 2

Hence, proved the above driven formula.Thus, the formula for (x-y-z)^2(x−y−z) 2 will be x^2+y^2+z^2-2xy+2yz-2xzx 2 +y

Hence, proved the above driven formula.Thus, the formula for (x-y-z)^2(x−y−z) 2 will be x^2+y^2+z^2-2xy+2yz-2xzx 2 +y 2

Hence, proved the above driven formula.Thus, the formula for (x-y-z)^2(x−y−z) 2 will be x^2+y^2+z^2-2xy+2yz-2xzx 2 +y 2 +z

Hence, proved the above driven formula.Thus, the formula for (x-y-z)^2(x−y−z) 2 will be x^2+y^2+z^2-2xy+2yz-2xzx 2 +y 2 +z 2

Hence, proved the above driven formula.Thus, the formula for (x-y-z)^2(x−y−z) 2 will be x^2+y^2+z^2-2xy+2yz-2xzx 2 +y 2 +z 2 −2xy+2yz−2xz

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