Question

x^2+y^2+z^2=202 find x,y,z​

Answer 1

This question can be solved by trial and error method.

That is, put possible values for x,y and z and check whether the conditions are matching.

Here after checking, the answer is,

x = 5 , y = 6 and z = 12

x² + y² + z² = 5² + 6² + 12² = 25 + 36 + 141 = 202

There can be other answers that satisfy this conditions.