Math, asked by DSTAR4019, 1 year ago

X^2+y^2-z^2+2xy/x^2-y^2-z^2-2yz

Answers

Answered by princessAngela
0
x²+y²-z²+2xy/x²-y²-z²-2yz
2xy+2yz
2(xy+yz)
Answered by Anonymous
4
Answer :


given \:    \:  {x}^{2}  + y {}^{2}  -  {z}^{2}  + \frac{2xy}{x {}^{2} }  -  {y}^{2}  -  {z}^{2}  - 2yz \\  \\  =  >  \: firstly \: eliminate \: the \: opposite \:  \\  \\  =  >  \: x {}^{2}  - z {}^{2}  +  \frac{2xy}{x {}^{2} }  - z {}^{2}  - 2yz \\  \\  =  >  \: simplify \:  \\  \\  =  >  \: x {}^{2}  - z {}^{2}  +  \frac{2y}{x}  - z {}^{2}  - 2yz \\  \\  =  >  \: collect \: like \: terms \\  \\  =  >  \: x {}^{2}  - 2z {}^{2}  +  \frac{2y}{x}  - 2yz \\  \\ write \: all \: numerators \: above \: l.c.m \\  \\  =  >  \:  \frac{x {}^{3} - 2xz {}^{2}  + 2y - 2xyz }{x}


Hope it would help you

Anonymous: sakshimaan Thanks
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