Question

x^2+y^2-z^2-2xyplease help me​

Answer 1

Answer:

Factorisation of is (x-y+z)(x-y-z).

Step-by-step explanation:

We have to factorise,

x^2+y^2-z^2-2xy

= x

^2+y^2-2xy-z^2\ [(a-b)^2 =a^2+b^2-2ab]

=

(x-y)^2-z^2\ [(a-b)(a+b)=a^2-b^2]

= (x-y+z)(x-y-z)    

Hence,factorisation of

x^2+y^2-z^2-2xy

is (x-y+z)(x-y-z)

Answer 2

Answer:

(x-y+z)(x-y-z)  

Step-by-step explanation

We have to factorise,

x^2+y^2-z^2-2xy

= x^2+y^2-2xy-z^2\ [(a-b)^2 =a^2+b^2-2ab]

= (x-y)^2-z^2\ [(a-b)(a+b)=a^2-b^2]

= (x-y+z)(x-y-z)