Math, asked by rajavarapuharika, 4 months ago

x^2+y^2+z^2=6 and (x/y+y/x)^2+(y/z+z/y)^2+(x/z+z/x)^2=165 then 1/x^2+1/y^2+1/z^2=

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Answered by krishnavijayan2006
0

Answer:

1

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