Question

(x^2+y^2+z^2)-(x^2-y^2+z^2)​

Answer 1

Answer:

$( {x}^{2} + {y}^{2} + {z}^{2} ) - ( {x}^{2} - {y}^{2} + {z}^{2} ) \\ = {x}^{2} + {y}^{2} + {z}^{2} - { {x}^{2} - ( - {y}^{2} } )+ z^{2} \\ = {y}^{2} + {y}^{2} \\ = 2 {y}^{2}$

Answer 2

Answer:

x^2+y^2+z^2-x^2+y^2-z^2

x^2-x^2+y^2+y^2+z^2-z^2

=2y^2