Question

x^2+y^2+z^2÷xy-yz-zx
if x=1 y=-2 z=3​

Answer 1

Answer:

14

Step-by-step explanation:

$(1) {}^{2} + ( - 2) {}^{2} + (3) {}^{2} \div (1)( - 2) - ( - 2)(3) - (3)(1)$

$1 + 4 + 9 \div - 2 + 6 - 3$

$14 \div 1$

$= 14$