Question

x^2+y^2=(z-c)^2 tan^2a
Answers for the above question
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Answer 1

Answer:

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Answer 2

Answer:

x2+y2+ (z-c) 2=a2

X2+y2+ (z-c) 2=a2 …………….> (1)

The above equation contains 2 arbitrary constants a & c

Differentiate equation (1) partial w.r.t, x we get

2x+2(z-c)

X+ (z-c) p=0 …….> (2)

Differentiate (1) partially w.r.t, ywe get

2y+2(z-c)

Y+ (z-c) q=0 ………> (3)