Question

x/2+y/3=13 2x/3+3y/4=10 using substitution method​

Answer 1

Answer:

x = 3y + 6. Putting, y = – 2, –1 and 0, we get. x = 3 × – 2 + 6 = – 6 + 6 =0. x = 3 × – 1 + 6 ... Subtracting 2x from both the sides, we get. y = 150 – 2x ... By substitution method. x + y = 5 ... ( i).

Answer 2

Answer:

ANSWER:

Disclaimer: There is error in the Q. In (II) there should have been 2x - 3y = 12

5x + 3y = 9 -----(I)

2x - 3y = 12 ----- (II)

Add (I) and (II)

7x = 21

x = 3

Putting the value of x = 3 in (I) we get

5(3)+3y=9⇒15+3y=9⇒3y=9-15=-6⇒y=-2

Thus, (x, y) = (3, -6).