Question

x/2 + y/3 = 2 & x/3 + y/2 = 13/6 using substitutional method​

Answer 1

Answer:

Step-by-step explanation:

The value of x is 2 and y is 3.

Step-by-step explanation:

……………………..(1)

……………………….(2)

Consider equation

By taking LCM for the denominator 2 and 3 we get the LCM as 6

9x – 10y = -12 ……………………….. (3)

Consider equation 2

By taking LCM for the denominator 3 and 2 we get the LCM as 6

2x + 3y = 13 …………………………(4)

By solving equation (3) and (4) we get

2x = 13-3y

x=13-3y/2 …………………………(5)

Put the value of x in eqn 3 we get

9[13-3y/2] – 10y =-12

117-27y-20y = -24                  [By taking LCM and solving it]

117-47y=-24

-47y=-24-117

-47y=-141

Y=-141/-47

Y=3

Now put the value of y =3 in (5)

x=13-3(3)/2

x=13-9/2

x=4/2

x=2

Therefore we have x=2 and y=3

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Answer 2

${\huge{\bf{\blue{HOLA!}}}}$

x/2 + y/3 =2 -----------(1)

x/3 + y/2 = 13/6 ----------(2)

from (1)

x/2+y/3 =2

3x+2y/6=2

3x+2y=12

3x=12-2y

x=12-2y/3

From (2)

x/3+y/2=13/6

2x+3y/6=13/6

2x+3y=13/6×6

2x+3y=13

putting value of x

2 (12-2y/3) + 3y = 13

24-6y/3 + 3y =13

24-6y+9y/3=13

24+3y =13×3

3y=39-24

3y= 15

y= 15/3

y = 5

From(1)

putting value of y in (1)

3x = 12-2y

3x= 12-2(5)

3x= 12-10

3x = 2

x = 2/3