Question

(x/2 + y/3)²
Using The Identity (a+b)² = a²+2ab+b²

Answer 1

Answer:

$( \frac{x}{2} + \frac{y}{3} ) {}^{2}$

consider x/2=a & y/3=b

$(a + b) {}^{2} = a {}^{2} + 2ab + b {}^{2}$

substitute according to the formula

$( \frac{x}{2} ) {}^{2} + 2( \frac{x}{2})( \frac{y}{3}) + ( \frac{y}{3}) {}^{2}$

now square the terms X the whole square is x²

and 2²is 4

and 2²is 4and in Y the whole square is y²

and 3² is 9

3² is 9now multiply the numerator (x)(y)= xy

similarly in the denominator (2)(3)=6

$\frac{ {x}^{2} }{4} + 2( \frac{xy}{6} ) + \frac{ {x}^{2} }{9}$

here 2 and 6 cancel with 3 (as 2 times 3 is 6)

$\frac{ {x}^{2} }{4} + \frac{xy}{3} + \frac{ {y}^{2} }{9}$

This is your final answer

hope this was helpful!