Question

(x/2+y/3)^3-(x/2-y/3)^3

Answer 1

Answer:

this is answer

Step-by-step explanation:

by this method it can be done

Answer 2

Answer:

2$x^{2}$y/4+2$y^{3}$/27

Step-by-step explanation:

expanding with $(a+b)^{3}$=($a^{3}$+3$a^{2}$b+3a$b^{2}$+$b^{3}$

expanding with $(a-b)^{3}$=($a^{3}$-3$a^{2}$b+3a$b^{2}$-$b^{3}$

($x^{3}$/8+$x^{2}$y/4+x$y^{2}$/6+$y^{3}$/27)-($x^{3}$/8-$x^{2}$y/4+x$y^{2}$/6-$y^{3}$/27)

opening the brackets,

$x^{3}$/8+$x^{2}$y/4+x$y^{2}$/6+$y^{3}$/27-$x^{3}$/8+$x^{2}$y/4-x$y^{2}$/6+$y^{3}$/27

=2$x^{2}$y/4+2$y^{3}$/27