Question

x/2+y/3=6
x/7+y/3=5 by elimination method​

Answer 1

$= > \frac{x}{2} + \frac{y}{3} = 6 \\ \: \: \: \frac{x}{7} + \frac{y}{3} = 5 \\ = > \frac{x}{3} - \frac{x}{7} = 1 \\ = > \frac{7x - 3x}{21} = 1 \\ = > 4x = 21 \\ = > x = \frac{21}{4} \\ = > \frac{ \frac{21}{4} }{2} + \frac{y}{3} = 6 \\ = > \frac{y}{3} = 6 - \frac{21}{8} \\ = > \frac{y}{3} = \frac{48 - 21}{8} \\ = > \frac{y}{3} = \frac{27}{8} \\ = > y = \frac{81}{8}$

hope this helps you

Answer 2

Answer:

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Step-by-step explanation:

x= 14/5 and y=69/5

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