Question

x=-2,y=3 so (x-y-2)^2-(x+y+1)-3​

Answer 1

Answer:

x = -2

y = 3

(x-y-2)²-(x+y+1)-3

(-2-3-2)²-(-2+3+1)-3

-2(-2-3-2)-3(-2-3-2)-2(-2-3-2) +2-3-1-3

4+6+4+6+9+6+4+6+4+2-3-1-3

8+12+9+12+8+2-7

44

Answer 2

$(x-y-2)^2-(x+y+1)-3\\x= -2 , and, y = 3\\= (-2-3-2)^2-(-2+3+1)-3\\=(-7)^2 - (2)-3\\=49-2-3\\=44$