Question

x/2=y/3=z/5, then x+y-z/x-y+z​

Answer 1

Answer:

0

Step-by-step explanation:

x/2=y/3=z/5=k(let)

Then x=2k, y=3k, z=5k

Now,

(x+y-z)/(x-y+z)=(2k+3k-5k)/(2k-3k+5k)

=0/4k =0