(x^2/y-4/x^2)^2 +2 solve using identities
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(a-b)²=a²-2ab+b²
[(x²/y)²-2(x²/y)(4/x²)+(4/x²)²
=(x²/y-4/x²)² +2
=x²/y²-8/y+16/x²+2
[(x²/y)²-2(x²/y)(4/x²)+(4/x²)²
=(x²/y-4/x²)² +2
=x²/y²-8/y+16/x²+2
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aashima27:
can u send me A pic of this ans
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