x/2 + y/5 =5; y/2 - x/3 = 3
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x=6 and y=10
5x+2y=50 and
3y-2x=18
now solve these equation by elimination method
I hope you will receive your answer.
5x+2y=50 and
3y-2x=18
now solve these equation by elimination method
I hope you will receive your answer.
Answered by
1
(5x+2y)/10=5
5x+2y=50..................(1)
(3y-2x)/6=3
3y-2x=18
-2x+3y=18.................(2)
Equation (1) is multiplied by 2 and equation (2) is multiplied by 5......
10x+4y=100..............(3)
-10x+15y=90................(4)
Equation (3) & (4) are added (sum)......
10x+4y=100
-10x+15y=90
______________
0+19y=190
y=190/19
y=10
the value of y is kept in equation (1)
5x+2y=50
5x+2(10)=50
5x+20=50
5x=50-20
5x=30
x=30/5
x=6
__________________________________
My answers are right or wrong? how can they check?
5(6)+2(10)=50
30+20=50
So, my answers are right.......
____________________________________
I hope it is helpful to you........
5x+2y=50..................(1)
(3y-2x)/6=3
3y-2x=18
-2x+3y=18.................(2)
Equation (1) is multiplied by 2 and equation (2) is multiplied by 5......
10x+4y=100..............(3)
-10x+15y=90................(4)
Equation (3) & (4) are added (sum)......
10x+4y=100
-10x+15y=90
______________
0+19y=190
y=190/19
y=10
the value of y is kept in equation (1)
5x+2y=50
5x+2(10)=50
5x+20=50
5x=50-20
5x=30
x=30/5
x=6
__________________________________
My answers are right or wrong? how can they check?
5(6)+2(10)=50
30+20=50
So, my answers are right.......
____________________________________
I hope it is helpful to you........
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