|x+2|+y=5 and x-|y|=1 then find value of x+y
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Answer:
x+y=1 or either x+y=12.5
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Value of x+y is 3
Step-by-step explanation:
Given:
We have |x+2|+y=5 and x-|y|=1
Here, x-|y|=1 ⇒ |y|=x-1
since |y| is always positive
x-1 will always be a positive number
That means x is always greater than equal to 1
So now the equations become,
x+2+y=5 [1]
x-y=1 [2]
Adding equation 1 and 2, we get
x+2+y+x-y=5+1
2x=6-2
x=2
Putting x=2 in equation 2
x-y=1
2-y=1
y=1
Now, x+y = 2+1 = 3
Hence value of x+y is 3
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