Question

x/2-y/b=0. 2x+by=b²+4. solution of the following pair of linear equations.?

a.x=0,y=1
b.x=1,y=0
c.x=2,y=b
d.x=b,y=2​

Answer 1

Answer:

your solution is as follows

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Step-by-step explanation:

$to \: find : \\ values \: of \: x \: and \: y \\ \\ given \: linear \: equations \: are \\ \frac{x}{2} - \frac{y}{b} = 0 \\ \\ bx = 2y \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: (1) \\ \\ 2x + by = b {}^{2} + 4 \: \: \: \: \: \: \: (2) \\ \\ 2x + b. \frac{bx}{2} = b {}^{2} + 4 \\ \\ 2x + \frac{b {}^{2} x}{2} = b {}^{2} + 4 \\ \\ 4x + b {}^{2} x = 2b {}^{2} + 8 \\ \\ x(b {}^{2} + 4) = 2(b {}^{2} + 4) \\ \\ x = 2 \\ \\ thus \: then \\ substituting \: value \: of \: x \: in \: (1) \\ we \: get \\ \\ y = b \\ \\ (x,y) = (2,b)$