X + 2 y is equals to 5, 3 x + k y - 15 is equals to zero find k when equation have unique solution and no solution
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This is the answer ..
eq_1
x. +2y =5
eq_2
3x + ky = 15
unique solution means...
a1/ a2 is not equal to b1/ b2 = c1/ c2
taking b1 / b2 = c1 / c2
2/k = 5 / 15
k = 6
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randhirkumar47:
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Answered by
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x + 2y = 5. *3
3x + ky =15
and subract we get
6y-ky = 0
y(6-k) = 0
6-k =0/y =0
then , k = 6
equation has unique solution
3x + ky =15
and subract we get
6y-ky = 0
y(6-k) = 0
6-k =0/y =0
then , k = 6
equation has unique solution
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