Math, asked by mdhrahman1122, 7 months ago

x√2=z+x,y√2=z+x,z√2=x+y then the value of 1/(x+1)+1/(y+1)+1/(z+1)​

Answers

Answered by saimondebbarma67
0

Answer:

√2=z+x,y√2=z+x,z√2=x+y then the value of 1/(x+1)+1/(y+1)+1/(z+1)

Step-by-step explanation:

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