Question

x=20+t^3-12t position when v=0

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Answer 1

Answer:

v=0

v=dx/dt=t²-12

0=t2-12

t²-12=0

t²=12

t=root12

t=root4x3

t=±2root3

Answer 2

Explanation:

Heya...!! Sis .

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Here is ur Answer ⬇⬇

1.) Given equation :- 20 + t^3 - 12t

At ,t = 0 =>> 20 + 0 - 0 = 20 m

♦ Position = 20 m

➡ Velocity = dx/dt = differentiating the equation given ,, we get ,, :--

=>> v = dx/dt = 3t^2 - 12

At t = 0 ,, v = - 12 m/s

♦ Velocity = - 12 m/s

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2.) Differentiating the equation ( 3t^2 + 12 ) we get acceleration . By getting acceleration we can determine wether motion is accelerated or not .

=>> a = dv/dt = 6t .

As we can see acceleration is a function of time , the Motion is Non Uniform Accelerated.

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