Question

X= 2019, y=2020, z=2021 find x²+y²+z²-xy-yz-zx

Answer 1

Answer:

Right ans is 2

please make me brain list

Answer 2

Answer:

x^2=4076361

y^2=(x^2)+(2x+1)=4080400

z^2=(y^2)+(2y+1)=4084441

xy=(y^2)-y=4078380

yz=(z^2)-z=4082420

zx=(z^2)-2z=4080399

ans=x^2+(x^2)+(2x+1)+[(x^2)+(2x+1)+2y+1]-[(x^2)+(2x+1)-y]-x-[(x^2)+(2x+1)+(2y+1)-z]-[(x^2)+(2x+1)+(2y+1)-2z]=

-2x-1-2y-1+y+3z=

-2x-1-y-1+3z=

-x-y-z+3z=

-x-y+2z=

-4039+4042=

3