X
22. Boat A travels due East from Port
S
P for 3 hours to reach Port Q and
then travels due South for another
2 hours to reach Port R. Boat B
Boat B
travels due North from Port Pfor
2 hours to reach Port S and then
P Boat A
travels due East for another 3 hours
to reach Port T. The average speed of
Boat A and Boat B are 12km/h and
18 km/h respectively.
Calculate the shortest distance between:
R
(1) Port Q and Port S
(ii) Port R and Port T.
Answers
Answered by
0
It is clear from the diagram that the shortest distance between the ship A and B is PQ.
Here, Sin45
0
=
OQ
PQ
⟹PQ=100×
2
1
=50
2
m
Also,
V
AB
=
V
A
2
+V
B
2
=
10
2
+10
2
=10
2
km/h
So, the time taken to reach shortest path is
t=
V
AB
PQ
=
10
2
50
2
=5h
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