Math, asked by kumarashwani4891, 10 months ago

x^+22x-48 please solve the question​

Answers

Answered by Anonymous
1

HeYa❤️...

Answer:

Correct question:

x {}^{2}  + 22x - 48

Solution:

x {}^{2}  + 22x - 48 = 0 \\ x {}^{2}  + (24 - 2)x - 48 = 0 \\ x {}^{2}  + 24x - 2x - 48 = 0 \\ x(x + 24) - 2(x + 24) = 0 \\ (x + 24)(x - 2) = 0

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Answered by ompatil18
0

Answer:

x^2+22x-48

We will take factors such as

24x-2x=22x

24*2=48

x^2+24x-2x-48

x(x+24)-2(x+24)

(x+24)(x-2) is answer

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