Math, asked by ratanjyoti, 1 year ago

(x-√24) (√75+√50) \√75-√50 =1 Find x value.

Answers

Answered by sahuraj457
31

 \frac{(x -  \sqrt{24})( \sqrt{75} +  \sqrt{50}  ) }{ \sqrt{75} -  \sqrt{50}  }  = 1 \\  \frac{(x - 2 \sqrt{6})(5 \sqrt{3}  + 5 \sqrt{2} ) }{5 \sqrt{3} - 5 \sqrt{2}  }  = 1 \\  \frac{(x - 2 \sqrt{6} )( \sqrt{3}  +  \sqrt{2}) }{ \sqrt{3} -  \sqrt{2}  }  = 1 \\   \frac{(x - 2 \sqrt{6}) {( \sqrt{3} +  \sqrt{2}  )}^{2}  }{3 - 2}  = 1 \\ (x - 2 \sqrt{6} )(5 + 2 \sqrt{6} ) = 1 \\ 5x + 2x \sqrt{6}  - 10 \sqrt{6}  - 24 = 1 \\ x(5 + 2 \sqrt{6} ) = 25 + 10 \sqrt{6}  \\ x(5 + 2 \sqrt{6} ) = 5(5 + 2 \sqrt{6} ) \\ x = 5
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ratanjyoti: thanks
Answered by saiswapna2006
7

Answer:

I hope it helps you. there is an another way to solve this question but it is way to complex.

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