Question

x)
24.
A particle moves in a circle with
speed of 15 m/s. The radiu
circle is 2 m. Determine the cent
acceleration of the particle,
[Ans: 112.5 ms
Can you reca
1. What are differe​

Answer 1

$\huge{\bold{\underline{\underline{....Answer....}}}}$

$\huge{\bold{\underline{Given:-}}}$

Velocity(v) = 15 m/s.

Radius(r) = 2m.

$\huge{\bold{\underline{Explanation:-}}}$

As we know,

$\large{\bold{a_{c} = \frac{v^2}{r}}}$

Substituting the values.

$\large{a_{c} = \frac{(15)^2}{2}}$

$\large{a_c = \frac{225}{2}}$

$\huge{\boxed{\boxed{a_c = 112.5 \: m/s^2}}}$

Additional formulas:-

$\large{\bold{ \star a_c = \omega^2r}}$

For Tangential acceleration

$\large{\bold{ \star a_T = \frac{dv}{dt}}}$

Total acceleration is given by:-

$\large{\bold{ \star a = \sqrt{(a_c)^2 + (a_T)^2}}}$

Answer 2

Answer:-

$\bold{a_c = 112.5 m{s}^{-2}}$

Explanation:-

Given:-

• v (velocity) = 15m/s
• r (radius) = 2m

To Find:-

Acceleration

Solution:-

W.k.t

$\boxed{\bold{a_c =\dfrac{{v}^{2}}{r}}}$

${\rightarrow}a_c =\dfrac{{15}^{2}}{2}$

${\rightarrow}a_c =\dfrac{225}{2}$

$\bold{{\rightarrow}a_c = 112.5 m{s}^{-2}}$