Math, asked by parth693, 9 months ago

x=-2a is the zero of the polynomial x^5-4a^2x^3+2x+2a+3 find the value of a​

Answers

Answered by swatianurish
1

Answer:

DJ

Step-by-step explanation:

Hi !

=_=

here is your answer,

given

x + 2a = 0

=> x = - 2a

so we get x = -2a

now set in

( -2a )^5 - 4. a^2 .( -2a )^3 + 2 ( -2a ) + 2a + 3

=> - 32a^5 + 32a^5 - 4a + 2a + 3

=> -4a + 2a + 3

=> - 2a +3

now

- 2a + 3 =0

=> a = -3/-2 = 3/2

value of a is = 3/2

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

Answered by prithiyankasree
1

Answer:

a=3/2

Step-by-step explanation:

( -2a )^5 - 4. a^2 .( -2a )^3 + 2 ( -2a ) + 2a + 3

=> - 32a^5 + 32a^5 - 4a + 2a + 3

=> -4a + 2a + 3

=> - 2a +3

- 2a + 3 =0

=> a = -3/-2 = 3/2

value of a is = 3/2

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