Question

x = 2at/1+t² y= b(1-t²)/1+t² find the value of x²/a² + y²/b²​

Answer 1

Answer:

$firstly \: substitute \: the \:valyes \: of \: x \: and \: y \: \\ = > \frac{ \frac{4 {a}^{2} }{ {(1 + {t}^{2} })^{2} } }{ {a}^{2} } \: + \frac{ \frac{ {b}^{2} (1 - {t}^{2} ) }{1 + {t}^{2} } }{ {b }^{2} } \\ = > \frac{5 - {t}^{2} }{ {(1 + {t}^{2} )}^{2} }$