Question

x+2i+15i6y=7x+i3(y+4) find x+y​

Answer 1

x+2i+15i6y=7x+i³(y+4)

x+2i+15(i²)³y=7x+(y+4)

x+2i+15(-1)³y=7x-i(y+4)

x+2i-15y-7x+iy+4i=0

-6x-15y+I(y+6)=0+0i

equating real and imaginary parts we get

-6x-15y=0

y+6=0

y=-6

-6x-15(-6)=0

-6x+90=0

x=-90/-6

x=15

x+y=15-6

x+y=9