Math, asked by Munch1234, 1 year ago

(x+2iy)(x-5iy)/(-x+3iy)(x+iy)​

Answers

Answered by ihrishi
2

Answer:

 \frac{(x + 2iy)(x - 5iy)}{( - x + 3iy)(x  + iy)}  \\  =  \frac{x (x - 5iy) +2iy (x - 5iy)}{- x (x  + iy) + 3iy(x  + iy)}  \\  = \frac{x^{2}  - 5ixy +2ixy  - 10i^{2} y^{2} }{- x^{2}    -  ixy + 3ixy  +3 i ^{2} y ^{2}} \\  =  \frac{ {x^{2} - 3ixy - 10( - 1)y}^{2} }{ -  {x}^{2}  + 2ixy + 3( - 1) {y}^{2} }  \\  = \frac{ {x^{2} - 3ixy  +  10y^{2}} }{ -  {x}^{2}  + 2ixy  -  3{y}^{2} }  \\ = \frac{ {x^{2} +  10y^{2}} \: - 3ixy   }{ -  {x}^{2} -  3{y}^{2} + 2ixy   } \:

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