x^-2kx+7x-12=0 find the value of k
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Answer:
Let's solve for k.
x^−2kx+7x−12=0
Step 1: Multiply both sides by x.
7x²+k−12x=0
Step 2: Add -7x²to both sides.
7x²+k−12x+−7x²=0+−7x²
k−12x=−7x²
Step 3: Add 12x to both sides.
k−12x+12x=−7x²+12x
k=−7x²+12x
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hello classmate
this is the answer
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kanishka
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