Question

x^(2n+7) * (x^2)^(3n+2) / x^(4(2n+3)​

Answer 1

Consider just the exponents:

Write as:

2

n

+

(

3

n

−

1

)

−

(

n

+

2

)

2

n

+

3

n

−

1

−

n

−

2

4

n

−

3

So we have:

x

4

n

−

3

This is positive for

n

>

3

4

As

n

is a counting number it is not likely to have

n

<

1

Answer 2

Answer:

= (x^2)^n+7 * (x^2)^3n+2 / x^4(2n+3)

= (x^2)^4n+9 / (x^2)^4n+6

= (x^2)^3

= (x^6)   ans....

Hope i think this answer is right.. and It may help you....!!!