x^2p+y^2q=(x+y) z
Solve the following PDE
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group-I
dx/x^2 =dy/y^2
integrating
-1/x+1/y=a
group-2
using multipliers 1,-1,0
[dx-dy/x^2 -y^2 ]=dz/=[x+y]*z)
[dx-dy/(x+y)(x-y)]=dz/(x+y)*z
d(x-y)/(x-y)=dz/z
integrating
log(x-y)=logz+logb
hence b=(x-y)/z
Therefore a= 1/y-1/x
b=x-y/z
I have tried to solve it.
If there is any mistake please rectify.
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