X=2root3+2root2 : find 1/x,x+1/x and (x+1/x)^2
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Answer:
X = 2 root 3 + 2 root 2
x = 2
Answered by
1
Hi ,
x = 2 - √3--( 1 )
1/x = 1/( 2 - √3 )
= ( 2 + √3 ) / [ ( 2 - √3 )(2 + √3 ) ]
= ( 2 + √3 ) / [ 2² - ( √3 )² ]
= ( 2 + √3 ) / ( 4 - 3 )
= 2 + √3 ----( 2 )
x - 1/x
= 2 - √3 - ( 2 + √3 )
= 2 - √3 - 2 - √3
= - 2√3 ---( 3 )
Therefore ,
( x - 1/x )³ = ( - 2√3 )³
= - 24√3
I hope this helps you.
x = 2 - √3--( 1 )
1/x = 1/( 2 - √3 )
= ( 2 + √3 ) / [ ( 2 - √3 )(2 + √3 ) ]
= ( 2 + √3 ) / [ 2² - ( √3 )² ]
= ( 2 + √3 ) / ( 4 - 3 )
= 2 + √3 ----( 2 )
x - 1/x
= 2 - √3 - ( 2 + √3 )
= 2 - √3 - 2 - √3
= - 2√3 ---( 3 )
Therefore ,
( x - 1/x )³ = ( - 2√3 )³
= - 24√3
I hope this helps you.
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