Math, asked by cpvibhamenon, 7 months ago

x=2root3. find x^3-1/x^3
pls help me ​

Answers

Answered by udayagrawal49
0

Answer:

x^{3}-\frac{1}{x^{3}} = \frac{1727\sqrt{3}}{72}

Step-by-step explanation:

Given: x = 2√3

x^{3}-\frac{1}{x^{3}} = (2\sqrt{3})^{3}-\frac{1}{(2\sqrt{3})^{3}}

x^{3}-\frac{1}{x^{3}} = 24\sqrt{3}-\frac{1}{24\sqrt{3}}

x^{3}-\frac{1}{x^{3}} = \frac{1728-1}{24\sqrt{3}}

x^{3}-\frac{1}{x^{3}} = \frac{1727}{24\sqrt{3}}

x^{3}-\frac{1}{x^{3}} = \frac{1727\sqrt{3}}{72}

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