Question

x(2x-3) =4+x (2x-5),solve for x​

Answer 1

$\large\sf\underline{Given}$

• $\sf\:x(2x-3) =4+x(2x-5)$

$\large\sf\underline{Solution :-}$

$\sf\:x(2x-3) =4+x(2x-5)$

$\sf↦\:2x^{2}-3x =4+2x^{2} -5x$

$\sf↦\:2x^{2} - 2x^{2} -3x+5x =4$

$\sf↦\:2x =4$

$\sf↦\:x =\frac{4}{2}$

$\tt\purple{↦\:2}$

• Thnku ❣

Answer 2

$\Huge\mathfrak\purple{{\rm{A}}nswe{\rm{R}}:}$

${}$

$\bf{{\underline{To~solve}}:}$

$\tt{~~~~~~~~~ x(2x-3)=4+x(2x-5)}$

$\tt{:\longmapsto 2x^{2}-3x=4+2x^{2}-5x}$

$\tt{:\longmapsto (2x^{2}-3x)-(2x^{2}-5x)=4}$

$\tt{:\longmapsto {\cancel{2x^{2}}}~-3x~~{\cancel{-2x^{2}}}+5x=4}$

$\tt{:\longmapsto -3x+5x=4}$

$\tt{:\longmapsto 2x=4}$

$\tt{:\longmapsto x={\dfrac{4}{2}}}$

$\tt{:\longmapsto x=\purple{\underline{\boxed{\bf 2}}}}$

$\bf\therefore{{\underline{Required~answer}}:}$

• $\tt{x=\purple{\underline{\boxed{\bf 2}}}}$