x(2x-3) =4+x (2x-5),solve for x
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Answered by
20
Answer:
x(2x-3) = 4+x(2x-5)
2x²-3x = 4+2x²-5x
5x-3x = 4+2x²-2x²
2x = 4
x=4/2
x=2
Answered by
3
Given : -
x(2x-3) =4+x (2x-5)
We have to find value of x
x (2x -3 ) = 4 + x(2x-5)
2x²-3x = 4+ 2x² -5x
Transpose RHS terms to LHS
2x² -3x -4 -2x² +5x =0
Putting Like terma together
2x² - 2x² -3x + 5x -4 =0
-3x + 5x -4 =0
2x - 4 = 0
Transpose 4 to RHS
2x = 4
Divide on both sides with 2
2x /2 = 4/2
x = 2
So, the value of x is 2
Verification:-
Substuite value of x to get LHS=RHS
x(2x-3) =4+x (2x-5)
2 (2×2 -3 ) = 4 + 2 (2×2-5)
2 (4-3) = 4 +2(4-5)
2(1) = 4+2(-1)
2 = 4-2
2 = 2
Hence verified
LHS =RHS
___________________
Know more :-
Multiplication of signs:-
(+) × (+) = +
(-) × (-) = +
(+) × (-) = -
(-) × (+) = -
If we multiply With same signs we get positive
If we multiply with opposite signs we get negative
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