Question

x+2x²+3x⁴-x⁵by 2x
guys please tell me fast ​
no bad answers

Answer 1

Answer:

Given:

\bold{\frac{3-x+2x^2+x^3-3x^4}{2-x}}

2−x

3−x+2x

2

+x

3

−3x

4

To Find:

Divide by division algorithm

Solution:

\Rightarrow \frac{3-x+2x^2+x^3-3x^4}{2-x}⇒

2−x

3−x+2x

2

+x

3

−3x

4

First, we rearrange the value:

\begin{gathered}\Rightarrow \frac{-3x^4+x^3+2x^2-x+3}{2-x}\\\\\end{gathered}

⇒

2−x

−3x

4

+x

3

+2x

2

−x+3

After arranging the value we divide:

\begin{gathered}\Rightarrow \frac{-3x^4+x^3+2x^2-x+3}{2-x}= 3x^3+5x^2+8x+17 +\frac{-31}{2-x}\\\\\end{gathered}

⇒

2−x

−3x

4

+x

3

+2x

2

−x+3

=3x

3

+5x

2

+8x+17+

2−x

−31