x+2x²+3x⁴-x⁵by 2x
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4
Answer:
Given:
\bold{\frac{3-x+2x^2+x^3-3x^4}{2-x}}
2−x
3−x+2x
2
+x
3
−3x
4
To Find:
Divide by division algorithm
Solution:
\Rightarrow \frac{3-x+2x^2+x^3-3x^4}{2-x}⇒
2−x
3−x+2x
2
+x
3
−3x
4
First, we rearrange the value:
\begin{gathered}\Rightarrow \frac{-3x^4+x^3+2x^2-x+3}{2-x}\\\\\end{gathered}
⇒
2−x
−3x
4
+x
3
+2x
2
−x+3
After arranging the value we divide:
\begin{gathered}\Rightarrow \frac{-3x^4+x^3+2x^2-x+3}{2-x}= 3x^3+5x^2+8x+17 +\frac{-31}{2-x}\\\\\end{gathered}
⇒
2−x
−3x
4
+x
3
+2x
2
−x+3
=3x
3
+5x
2
+8x+17+
2−x
−31
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