x-2y=0 and 3x+4y=20 solve
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Answered by
4
Answer:
x-2y=0___(1) ×3
3x+4y=20___(2)
________
3x-6y=0
3x+4y=20
_______
2y=-20
y=-10
from equation (1)
x+20=0
x=-20
Answered by
12
ANSWER:
- Value of x is 4 and y is 2.
GIVEN:
- x-2y = 0
- 3x+4y = 20
TO FIND:
- Value of 'x'and 'y'.
SOLUTION:
=> x-2y = 0
=> x = 2y .....(I)
=> 3x+4y = 20 ......(ii)
Putting x = 2y in eq(ii) we get;
=> 3(2y)+4y = 20
=> 6y+4y = 20
=> 10y = 20
=> y = 20/10
=> y = 2
Putting y = 2 in eq(I)
=> x = 2(2)
=> x = 4
Value of x is 4 and y is 2.
This method of finding the value of x and y is called substitution method.
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