Question

x-2y=0 and 3x+4y=20 solve

Answer 1

Answer:

x-2y=0___(1) ×3

3x+4y=20___(2)

________

3x-6y=0

3x+4y=20

_______

2y=-20

y=-10

from equation (1)

x+20=0

x=-20

Answer 2

ANSWER:

• Value of x is 4 and y is 2.

GIVEN:

• x-2y = 0
• 3x+4y = 20

TO FIND:

• Value of 'x'and 'y'.

SOLUTION:

=> x-2y = 0

=> x = 2y .....(I)

=> 3x+4y = 20 ......(ii)

Putting x = 2y in eq(ii) we get;

=> 3(2y)+4y = 20

=> 6y+4y = 20

=> 10y = 20

=> y = 20/10

=> y = 2

Putting y = 2 in eq(I)

=> x = 2(2)

=> x = 4

Value of x is 4 and y is 2.

This method of finding the value of x and y is called substitution method.