Question

x+2y+1=0,2x-3y-12=0,solve by cross multipication​

Answer 1

Answer:

x=(b1c2-b2c1)÷(a1b2-a2b1)

(2×(-12)-(-3)×1)÷(1×(-3)-2×2)

(-24+3)÷(-3-4)

(-21)÷(-7)

3

y=(c1a2-c2a1)÷(a1b2-a2b1)

(1×2-(-12)×1)÷(1×(-3)-2×2)

(2+12)÷(-3-4)

14÷(-7)

-2

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