Math, asked by panchalatul300, 3 months ago

x-2y=-10 ; 3x-5y=-12 solve by equating coefficient method​

Answers

Answered by tannyamyr2005
2

Step-by-step explanation:

x−2y=−10 ...(i)

3x−5y=−12 ...(ii)

On multiplying (i) by 3, we get

3x−6y=−30 ...(iii)

now subtracting (ii) from (iii)

3x−6y=−30

3

x

+

5y=

+

12

−y=−18

∴y=18

On putting y=18 in (ii), we get

3x−5(18)=−12

3x−90=−12

3x=78

x=26

∴x=26,y=18

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