x-2y+2=0 & 2x+ky-1=0 have the same y intercept
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Answer:
x-2y+2=0
x+2y=-2
x+y=-2/2
x+y=-1
x=-1-y
y=-1-x
2x+ky-1=0
2(-1-y)+k(-1-x)-1=0
2(-1-y)+k(-1-x)=1
-2-2y+(-k-kx)=1
-2y-k-kx=1+2
-2y-k-kx=3
y-k-kx=3/-2
y-k-kx=-1.5
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