Question

(x+2y)^2-1 factorize completely​

Answer 1

Answer:

Here is your answer

(x+2y)^2-(1)^2

=(x+2y+1)(x+2y-1)

Answer 2

Answer:

$(x + 2y) {}^{2} - 1 \\ = (x + 2y - 1)(x + 2y + 1)$

OR

$(x + 2y) {}^{2} - 1 \\ = {x}^{2} + 4y {}^{2} + 2xy - 1$

Formula used :

• ${x}^{2} - {y}^{2} = (x - y)(x + y)$
• $(x + y) {}^{2} = {x}^{2} + {y}^{2} + 2xy$