Question

x^2y^2 -8xy -48


factorise ​

Answer 1

$\mathfrak{\large{\underline{\underline{Answer:-}}}}$

By using middle splitting term let's factories:-

$\{(xy)}^{2} - 8xy - 48 = 0$

$\implies$ $\ {x}^{2} {y}^{2} + 4xy - 12xy - 48= 0$

Taking common,

$\implies$ $\xy(xy + 4) - 12(xy + 4) = 0$

$\implies$(xy + 4)(xy - 12) = 0

$\implies$ xy + 4 = 0 either xy - 12 = 0

$\implies$ xy = -4 either xy = 12

Answer 2

Answer:

x

2

y

2

−8xy−48

x

2

y

2

−12xy+4xy−48

Take out common in all terms we get,

xy(xy−12)+4(xy−12)

(xy−12)(xy+4)

Step-by-step explanation:

hope it helps you