x^2y^2-ny-73 how to solve
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1
Answer:
eq1 :
x
+
y
+
z
=
73
eq2 :
−
2
x
+
2
y
=
8
eq3 :
x
−
z
=
−
9
Now eq2 can be written as
−
x
+
y
=
4
or
y
=
4
+
x
(divide by
2
)
and eq3 can be written as
z
=
x
+
9
Now we replace the values of
y
and
z
in eq1 hence
x
+
(
4
+
x
)
+
(
x
+
9
)
=
73
3
x
+
13
=
73
3
x
=
60
x
=
20
Now replace the value of
x
in eq2 and eq3 to get the values of
y
and
z
hence
y
=
4
+
x
=
4
+
20
=
24
z
=
x
+
9
=
20
+
9
=
29
Finally the solution of the system is
(
x
,
y
,
z
)
=
(
20
,
24
,
29
Step-by-step explanation:
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