Question

(x+2y)²-(x-2y)² find with identity​

Answer 1

either x=0 or y=0

Step-by-step explanation:

(x+2y)²-(x-2y)² =0

$x^{2} +4y^{2}+8xy- x^{2} -4y^{2}+8xy=0\\8xy=0\\xy =0$

=> either x=0 or y=0