(x+2y)+(2x-3y)i+4i=5 find the value of x and y .
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Here conjugate of 5+4i is 5-4i
and (a+2y)+i(2x-3y) is the conjugate of 5+4i
ie (x+2y)+i(2x-3y)=5-4i
comparing real parts and imaginary parts we get
x+2y=5 and 2x-3y=-4 _________ (1)
⇒x=5−2y
substituting value of x is (ii), we get
2(5-2y)-3y=-4
10-4y-3y=-4
⇒7y=14
⇒y=2.
from (1), x=5-2(2)=5-4
∴x=1
since x=1, y=2.
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