X+2y-3=0,3x+2y+7=0 by elimination method
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Answered by
6
Answer:
HEYA MATE
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HERE IS YOUR ANSWER
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x + 2y - 3 = 0.....(1)
3x + 2y + 7 = 0.....(2)
Subtract eqn.(2) from eqn.(1)
x + 2y - 3 = 0
3x + 2y + 7 = 0
Signs will be changed
=> -3x -2y -7 = 0
2y and -2y will be cancelled
so, required equation would be
-2x - 10 = 0
-2x = 10
x = -5
put x = -5 in eqn.(1)
-5 + 2y -3 = 0
-8 + 2y = 0
2y = 8
y = 4
Therefore, x = -5 and y = 4 is the required solution
HOPE IT HELPS YOU
PLZ MARK AS BRAINLIEST
Answered by
2
Answer:
X+2y-3=0-----(1)
3x+2y+7=0-----(2)
From equation 1 or 2
Subtract both equation
So
2x=-10
X=-5
Put X in first (1)
(-5)+2y+7=0
2+2y=0
2y=-2
Y=-1
So:
Y=-1andx=-5
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