CBSE BOARD X, asked by palakpreetkaur87621, 9 months ago

X+2y-3=0,3x+2y+7=0 by elimination method

Answers

Answered by Roop1479
6

Answer:

HEYA MATE

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HERE IS YOUR ANSWER

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x + 2y - 3 = 0.....(1)

3x + 2y + 7 = 0.....(2)

Subtract eqn.(2) from eqn.(1)

x + 2y - 3 = 0

3x + 2y + 7 = 0

Signs will be changed

=> -3x -2y -7 = 0

2y and -2y will be cancelled

so, required equation would be

-2x - 10 = 0

-2x = 10

x = -5

put x = -5 in eqn.(1)

-5 + 2y -3 = 0

-8 + 2y = 0

2y = 8

y = 4

Therefore, x = -5 and y = 4 is the required solution

HOPE IT HELPS YOU

PLZ MARK AS BRAINLIEST

Answered by komalrathee19
2

Answer:

X+2y-3=0-----(1)

3x+2y+7=0-----(2)

From equation 1 or 2

Subtract both equation

So

2x=-10

X=-5

Put X in first (1)

(-5)+2y+7=0

2+2y=0

2y=-2

Y=-1

So:

Y=-1andx=-5

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