(x-2y)^3 + ( 2y-3z)^3 + (3z-x)^3
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Answered by
13
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khushi950:
answer is 0
hmmm
plzzzzzzzzzzzzzzzzzzzzssszzzzzSs reply⬅
answer is zero?
If we will further factorise using (a-b)^3 identity, it will be zero
okkk
i understand
thanks
Answered by
7
HELLO.........FRIEND!!
THE ANSWER IS HERE,
(x-2y)^3 +(2y-3z)^3 +(3z-x)^3
This is in the form of
=> a^3 +b^3 +c^3
So, Lets find the value of a+b+c.
=> x-2y+(2y-3z)+(3z-x)
=> x-2y+2y-3z+3z-x
=> 0.
Here, a+b+c =0. So,
a^3 +b^3 +c^3 = 3abc
=> 3 (x-2y)(2y-3z)(3z-x)
THE ANSWER IS HERE,
(x-2y)^3 +(2y-3z)^3 +(3z-x)^3
This is in the form of
=> a^3 +b^3 +c^3
So, Lets find the value of a+b+c.
=> x-2y+(2y-3z)+(3z-x)
=> x-2y+2y-3z+3z-x
=> 0.
Here, a+b+c =0. So,
a^3 +b^3 +c^3 = 3abc
=> 3 (x-2y)(2y-3z)(3z-x)
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